Split 64 into three parts such that the numbers are in G.P.

Split 69 in three parts such that they are in A.P. and product of two smaller parts is 483.

Three positive numbers form an increasing GP. If the middle term in this GP is doubled, then new numbers are in AP. Then, the common ratio of the GP is

The fourth, seventh, and the last term of a G.P. are 10, 80, and 2560, respectively. Find the first term and the number of terms in G.P.

Three numbers form an increasing G.P. If the middle number is doubled, then the new numbers are in A.P. The common ratio of the G.P. is

Three numbers from an increasing G.P. If the middle term is doubled the new number are in A.P. The common ratio of G.P will be

Three non zero numbers a, b, c are in A.P. Increasing a by 1 or increasing c by 2, the number become in G.P then b equals

Suppose three real numbers a , b , c are in G.P. Let z=(a+ib)/(c-ib) . Then

Find a three – digit number such that its digits are in increasing G.P. (from left to right) and the digits of the number obtained from it by subtracting 100 form an A.P.

The consecutive digits of a three digit number are in G.P. If middle digit is increased by 2, then they form an A.P. If 792 is subtracted from this, then we get the number constituting of same three digits but in reverse order. Then number is divisible by a. 7 b. 49 c. 19 d. none of these

Let f(x)=2x+1. Then the number of real number of real values of x for which the three unequal numbers f(x),f(2x),f(4x) are in G.P. is 1 b. 2 c. 0 d. none of these