Home
Class 10
MATHS
The equatin of a line passing through th...

The equatin of a line passing through the origin and perpendicular to the line `7x-3y+4=0` is

A

7x-3y+4=0

B

3x-7y+4=0

C

3x+7y=0

D

7x-3y=0

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • CO-ORDINATE GEOMETRY

    PREMIERS PUBLISHERS|Exercise Unit Exericise|10 Videos
  • CO-ORDINATE GEOMETRY

    PREMIERS PUBLISHERS|Exercise Thinking Corner|8 Videos
  • CO-ORDINATE GEOMETRY

    PREMIERS PUBLISHERS|Exercise Exercise 5.4|15 Videos
  • ALGEBRA

    PREMIERS PUBLISHERS|Exercise OTHER IMPORTANT OBJECTIVE TYPE QUESTIONS (Match the following)|4 Videos
  • GEOMETRY

    PREMIERS PUBLISHERS|Exercise OTHER IMPORTANT OBJECTIVE TYPE QUESTIONS|22 Videos

Similar Questions

Explore conceptually related problems

The equation of a line passing through the origin and perpendicular to the line 7x-3y+4=0 is ……..

The equation of the line passing through origin and perpendicular to the line 7x – 3y + 4 = 0

The equation of a line through origin and perpendicular to the line 23x-11y+7=0 is :

Write the equation of the line passing through the point (1,-1) and parallel to the line x+3y -4=0

Find the equation of the pair of straight lines passing through the point (1,3) and perpendicular to the lines 2x-3y+1=0 and 5x+y-3=0.

Equation of the passing through the origin and perpendicular to the planes x+2y+z=1 , 3x-4y+z=5 is

Find the equation of pair of lines through the origin and perpendicular to the pair of lines 2x^(2)+11xy+12y^(2)=0