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sec(90^(@)-theta)= ………………...

`sec(90^(@)-theta)=` ………………

A

`cosectheta`

B

`tantheta`

C

`sintheta`

D

`costheta`

Text Solution

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The correct Answer is:
A
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Prove that sin (270^(@)-theta) sin (90^(@)-theta)-cos(270^(@)-theta) cos (90^(@)+theta)+1=0

Prove that (sin(90^(@)-theta))/(1+sintheta)+(costheta)/(1-cos(90^(@)-theta))=2sectheta

Knowledge Check

  • The value of cosec(70^(@)+theta)-sec(20^(@)-theta)+tan(65^(@)+theta)-cot(25^(@)-theta) is……………..

    A
    0
    B
    1
    C
    2
    D
    3

  • (1-Sin^(2)theta)(sec^(2)theta)= ………… .

    A
    0
    B
    1
    C
    `tan^(2)theta`
    D
    `cos^(2)theta`

  • 9tan^(2)theta-9sec^(2)theta= ………… .

    A
    1
    B
    0
    C
    9
    D
    -9

    • Similar Questions

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    Prove that -(cot (180^(@) + theta) sin (90^(@) - theta) cos (-theta))/(sin (270^(@) + theta) tan(-theta) coses (360^(@) + theta)) = cos^(2) theta cot theta .

    Prove that (cot(180^(@) + theta) sin (90^(@)-theta) cos(-theta))/(sin(270^(@) + theta) tan(-theta) "cosec"(360^(@) + theta)) = cos^(2)theta cot theta .

    Simplify (cos(90^@+theta)sec (-theta)tan(180^(@)-theta))/(sec(360^(@)-theta)sin(180^(@)+theta)cot (90^(@)+theta))

    sin(90^(@)-theta)costheta+cos(90^(@)-theta)sintheta= ………… .

    The value of "cosec" ( 70^(@) + theta) - sec ( 20^(@) - theta) + tan ( 65 ^(@) + theta) - cot ( 25 ^(@) - theta) is

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