[" Let A be an n order square matrix and "B" be its adjoint,then "|AB+K_(n)|*" where "K" is "],[" a scalar quantity "]

Let A be an n order square matrix and B be its adjoint, then |AB + KI_(n)| , where K is a scalar quantity. a) (|A| + K)^(n-2) b) (|A| +K)^(n) c) (|A| + K)^(n - 1) d)None of these

Let A be an nth-order square matrix and B be its adjoint, then |A B+K I_n| is (where K is a scalar quantity)

Let A be an nth-order square matrix and B be its adjoint,then |AB+KI_(n)| is (where K is a scalar quantity (|A|+K)^(n-2) b.(|A|+)K^(n) c.(|A|+K)^(n-1) d.none of these

Let A be an nth-order square matrix and B be its adjoint, then |A B+K I_n| is (where K is a scalar quantity) a. (|A|+K)^(n-2) b. (|A|+K)^n c. (|A|+K)^(n-1) d. none of these

Let A be an nth-order square matrix and B be its adjoint, then |A B+K I_n| is (where K is a scalar quantity) (|A|+K)^(n-2) b. (|A|+K)^n c. (|A|+K)^(n-1) d. none of these

Let A be an nth-order square matrix and B be its adjoint, then |A B+K I_n| is (where K is a scalar quantity) a. (|A|+K)^(n-2) b. (|A|+K)^n c. (|A|+K)^(n-1) d. none of these

Let A be an nth-order square matrix and B be its adjoint, then |A B+K I_n| is (where K is a scalar quantity) (|A|+K)^(n-2) b. (|A|+)K^n c. (|A|+K)^(n-1) d. none of these

Let A be an nth-order square matrix and B be its adjoint, then |A B+K I_n| is (where K is a scalar quantity) a. (|A|+K)^(n-2) b. (|A|+K)^n c. (|A|+K)^(n-1) d. none of these

If A be an n-square matrix and B be its adjoint, then show that Det (AB + KI_(n)) = [Det (A) + K]^(n) , where K is a scalar quantity.

Let A be a square matrix of order 'n' then abs[KA]=