What is the angles subtended by 1 m pole at a distance 1 km on the ground in sexagesimal measure ?

What is the angle subtended by 1 m pole at distance 1 km on the ground in sexagesimal measure?

A pole 25 meters long stands on the top of a tower 225 meters high. It theta is the angle subtended by the pole at a point on the ground which is at distance 2.25 km, from the foot of the tower, then tan theta is equal to

The circular measures of two of the angles of a triangle are 1/2 and 1/3 . Express the third angle in sexagesimal measure.

A vertical pole fixed to the ground is divided in the ratio 1:9 by a mark on it with lower part shorter than the upper part. If the two parts subtend equal angles at a place on the ground, 25 m away from the base of the pole, what is the height of the pole?

A vertical pole subtends an angle Tan^-1(1/2) at a point P on the ground. IF the angles subtended by the upper half and the lower half of the pole at P are respectively alpha and beta , then (tan alpha , tan beta) =

The ratio of two angles subtended by two arcs of unequal lenghts at the centre is 5:2 and if the sexagesimal value of the second angle is 30^(@) , then detrmine the sexagesimal value and the circular value of the first angle.

A tower of height 5m and a flagstaff on top of the tower subtend equal angles at a point on the ground, distance 13m from the base of the tower. The height of the flagstaff is

A vertical pole fixed to the horizontal ground is divided in the ratio 3 : 7 by a mark on it with lower part shorter than the upper part. If the two parts subtend equal angles at a point on the ground 18 m away from the base of the pole, then the height of the pole (in meters) is :