Statement 1:Three consecutive binomial coefficients are always in A.P. Statement 2: Three consecutive binomial coefficients are not in H.P. or G.P.

Show that no three consecutive binomial coefficients can be in ( i ) G.P.,(ii) H.P.

The ratio of three consecutive binomial coefficients in the expansion of (1+x)^n is 2:5:12 . Find n.

Statement 1 : 3,6, 12 are in GP, then 9, 12, 18 are in H. P.Statement 2: If three consecutive terms of a G.P. are positive and if middle term is added in these terms,then resultant will be in H.P(A)STATEMENT-1 is true, STATEMENT-2 is true and STATEMENT-2 is correct explanation forSTATEMENT-1STATEMENT-1 is true, STATEMENT-2 is true and STATEMENT-2 is not correct explanation forSTATEMENT-1STATEMENT-1 is true, STATEMENT-2 is falseSTATEMENT-1 is false, STATEMENT-2 is true(B)(C)(D)

If binomial coeffients of three consecutive terms of (1 + x )^(n) are in H.P., then the maximum value of n, is

If 4/5,x,2 are three consecutive terms of an A.P then find x

In the expansion of (1+x)^(n) the binomial coefficients of three consecutive terms are respectively 220,49 and 792 find the value of n .

If three consecutive coefficients in the expansion of (1+x)^(n) be 56,70 and 56, find n and the position of the coefficients.