` x^(4) - 227 = 398, y^(2) + 321 = 346`

In the following questions two equation numbered I and II are given You have to solve both equations and . . . . . (i) x^(4)-227=398 (ii) y^(2)+321=346

I. x^(2) - 463 = 321 II. y^(2) - 421 = 308

If 346 xx 192=66432 then, find the answer given below. a) 3.46 xx 192 = b) 34.6 xx 1.92= c) 346 xx 19.2= d) 3.46 xx .192 = e) 346 xx .192=

Find the length of the perpendicular from ( 3,2,1) to the line (x - 7) /(-2) = (y - 7)/(2) = (z - 6 ) /(3) .

If the [[4,12,1]] ^ (2) = the [[3,21, x]] - the [[x, 3-2,1]] then x =

If the [[4,12,1]] ^ (2) = the [[3,21, x]] - the [[3,3-2,1]], then x =

Length of perpendicular from the point (3,2,1) to the line (x-7)/2 = (y-7)/(-2) = (z - 6)/(-3) is

The perpendicular distance of the point (3,2,1) from the plane 3x+4y-2z - 10 = 0 is...............