`sqrt(3i)+sqrt(-3i)=` (i) `+-2sqrt3` (ii) `+-sqrt6` (iii)`3` (iv)`3i`

sqrt(3i)+sqrt(-3i)=(i)+-2sqrt(3)(ii)+-sqrt(6)(iii)3(iv)3i

sqrt(3)+(sqrt(3)-i2)-(3-i2)

(sqrt(3+4i)+sqrt(3-4i))/(sqrt(3+4i)-sqrt(3-4i))=

(sqrt(3)+i)^(6)+(sqrt(3)-i)^(6)=

(i) 3sqrt(5) by 2sqrt(5) ,(ii) 6sqrt(15) by 4sqrt(3) , (iii) 2sqrt(6) by 3sqrt(3) (iv) 3sqrt(8) by 3sqrt(2) ,(v) sqrt(10) by sqrt(40) , (vi) 3sqrt(28) by 2sqrt(7)

Values (s)(-i)^(1/3) is/are (sqrt(3)-i)/2 b. (sqrt(3)+i)/2 c. (-sqrt(3)-i)/2 d. (-sqrt(3)+i)/2

Values (s)(-i)^(1/3) is/are (sqrt(3)-i)/2 b. (sqrt(3)+i)/2 c. (-sqrt(3)-i)/2 d. (-sqrt(3)+i)/2

Values (s)(-i)^(1/3) is/are (sqrt(3)-i)/2 b. (sqrt(3)+i)/2 c. (-sqrt(3)-i)/2 d. (-sqrt(3)+i)/2

Let z_1=((1+sqrt(3)i)^2(sqrt(3)-i))/(1-i) and z_2=((sqrt(3)+i)^2(1-sqrt(3)i))/(1+i) then

Simplify: (i) (2 sqrt(2) + 3 sqrt(3)) (2 sqrt(2) - 3 sqrt(3)) (ii) (2 sqrt(8) - 3 sqrt(2))^(2) (iii) (sqrt(7) + sqrt(6))^(2) (iv) (6 - sqrt(2))(2 + sqrt(3))