The value of 1/(2!)+1/(4!)+1/(6!)+... is...

The value of `1/(2!)+1/(4!)+1/(6!)+...` is

A

`(e^(2) + 1)/(2e)`

B

`(e+1)^(2)/(2e)`

C

`(e-1)^(2)/(2e)`

D

`(e^(2)+1)/(2e)`

Verified by Experts

The correct Answer is:

C

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