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The normal boiling point of water is 100...

The normal boiling point of water is `100^(@)C` or `212^(@)F` and the freezing point of water is `0^(@)C` or `32^(@)F`.
Find the value of C for `98.6^(@)F`

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The correct Answer is:
`(333)/(9)=(37^(@)C`
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PREMIERS PUBLISHERS-TWO DIMENSIONAL ANALYTICAL GEOMETRY-SOLUTION TO EXERCISE (6.2)
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