Show that if one of angle betwwen pair of straight lines `ax^(2)+2hxy+by^(2)=0` is `60^(@)` then `(a+3b)(3a+b)=4h^(2)`

If h^(2)=ab then the angle between the pair of straight lines given by ax^(2)+2hxy+by^(2)=0 is

If h^(2)=ab then the angle between the pair of straight lines given by ax^2+2hxy+by^2=0 is

The condition that the pair of straight lines ax^(2)+2xy+by^(2)=0 are parallel is:

Find the separate equation of the following pair of straight lines 3x^(2)+2xy-y^(2)=0

The lines y = mx bisects the angle between the lines ax^(2) +2hxy +by^(2) = 0 if

Find the angle between the pair of straight lines given by (a^(2)-3b^(2))x^(2)+8ab xy+(b^(2)-3a^(2))y^(2)=0

The slope of one of the straight lines ax^(2)+2hxy+by^(2)=0 is three times the other, show that 3h^(2)=4ab .

The slope of one of the straight lines ax^(2)+2hxy+by^(2)=0 is twice that of the other, show that 8h^(2)=9ab .

Through a point A on the x-axis, a straight line is drawn parallel to the y-axis so as to meet the pair of straight lines a x^2+2h x y+b y^2=0 at B and Cdot If A B=B C , then (a) h^2=4a b (b) 8h^2=9a b (c) 9h^2=8a b (d) 4h^2=a b