Home
Class 11
MATHS
Prove that f(x)=2x^(2)+3x-5 is continuou...

Prove that `f(x)=2x^(2)+3x-5` is continuous at all points in `RR`.

Text Solution

Verified by Experts

The correct Answer is:
`f(x_o)`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • DIFFERENTIAL CALCULUS LIMITS AND CONTINUITY

    PREMIERS PUBLISHERS|Exercise SOLUTION TO EXERCISE 9.6|25 Videos
  • DIFFERENTIAL CALCULUS LIMITS AND CONTINUITY

    PREMIERS PUBLISHERS|Exercise PROBLEMS FOR PRACTICE|58 Videos
  • DIFFERENTIAL CALCULUS LIMITS AND CONTINUITY

    PREMIERS PUBLISHERS|Exercise SOLUTION TO EXERCISE 9.4|28 Videos
  • DIFFEREMTIAL CALCULUS DIFFERENTIABILITY AND METHODS OF DIFFERENTITAION

    PREMIERS PUBLISHERS|Exercise PROBLEMS FOR PRACTICE|73 Videos
  • EXAMINATION QUESTION PAPER MARCH 2019

    PREMIERS PUBLISHERS|Exercise PART -IV|4 Videos

Similar Questions

Explore conceptually related problems

Show that f(x)=|3x-2|/(3x-2) is continuous at x=2/3

Prove that the function f(x)= 5x-3 is continuous at x=0, at x= -3" and at " x=5 .

Is the function defined by f(x)= x^(2)-sin x+5 continuous at x= pi ?

Consider f(x,y)=(xy)/(x^2+y^2) if (x,y) ne (0,0) and f (0,0) = 0 . Show that f is not continuous at (0,0) and continuous at all other points of R^2.

Let f (x,y) = (2xy)/(x ^(2)+2y ^(2)) (x,y) ne (0,0) =0 if (x,y) = (0,0) Show that f (x,y) is not continuous at (0,0) through continuous at all other points of R ^(2).

f(x)={a x(x-1)+b ,x 3 Find the values of the constants a , b , pa n dq so that all the following conditions are satisfied f(x) is continuous for all xdot f(1) does not exist. f^(prime)(x) is continuous at x=3

if f(x)={x^3 x<0 3a+x^2 x≥0 is continuous at x = 0 , then a is

If graph of the function y=f(x) is continuous and passes through point (3, 1) then lim_(xrarr3) (log_(e)(3f(x)-2))/(2(1-f(x))) is equal

A function f(x) satisfies the following property: f(xdoty)=f(x)f(y)dot Show that the function f(x) is continuous for all values of x if it is continuous at x=1.

Find the values of k so that the function f is continuous at the indicated point. f(x)={{:(kx+1," if "x le 5),(3x-5," if "x gt 5):}" at "x= 5 .