Home
Class 11
MATHS
f(x)={(x,0,le,x,le,1),(2x,-,1,1,lt,x,le,...

`f(x)={(x,0,le,x,le,1),(2x,-,1,1,lt,x,le,2):}` then `f'(1^(-))` is :

A

1

B

0

C

`1/2`

D

Does not exist

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Topper's Solved these Questions

  • DIFFEREMTIAL CALCULUS DIFFERENTIABILITY AND METHODS OF DIFFERENTITAION

    PREMIERS PUBLISHERS|Exercise SOLUTION TO EXERCISE 10.5|25 Videos
  • COMBINATORICS AND MATHEMATICAL INDUCTION

    PREMIERS PUBLISHERS|Exercise PROBLEMS FOR PRACTICE (Choose the correct option for the following)|34 Videos
  • DIFFERENTIAL CALCULUS LIMITS AND CONTINUITY

    PREMIERS PUBLISHERS|Exercise PROBLEMS FOR PRACTICE|58 Videos

Similar Questions

Explore conceptually related problems

f(x)={(x,0,le,x,le,2),(3x,-,1,2,lt,x,le,3):} then f'(2^(+)) is:

f(x)={(2x,-,3,0,le,x,le,2),(x^(2),-,3,2,le,x,le,4):} then f'(2^(+)) and f'(2^(-)) are:

If the function f(x)={(x+1",",x le 1),(2x+1",",1lt x le 2):} and g(x)={(x^(2)",", -1 le x lt2),(x+2",",2le x le 3):} then the number of roots of the equation f(g(x))=2

Consider the functions f(x)={(x+1",",x le 1),(2x+1",",1lt x le 2):} and g(x)={(x^(2)",", -1 le x lt2),(x+2",",2le x le 3):} The domain of the function f(g(x)) is

Consider the functions f(x)={(x+1",",x le 1),(2x+1",",1lt x le 2):} and g(x)={(x^(2)",", -1 le x lt2),(x+2",",2le x le 3):} The range of the function f(g(x)) is

Consider two functions f(x)={([x]",",-2le x le -1),(|x|+1",",-1 lt x le 2):} and g(x)={([x]",",-pi le x lt 0),(sinx",",0le x le pi):} where [.] denotes the greatest integer function. The number of integral points in the range of g(f(x)) is

Two functions are defined as under : f(x)={(x+1, x le 1), (2x+1, 1 < x le 2):} and g(x)={(x^2, -1 le x le 2), (x+2, 2 le x le 3):} Find fog and gof

The number of point f(x) ={{:([ cos pix],0le x lt1),( |2x-3|[x-2],1lt xle2):} is discontinuous at Is ([.] denotes the greatest intgreal function )

f(x)={(x-1",",-1 le x le 0),(x^(2)",",0le x le 1):} and g(x)=sinx Consider the functions h_(1)(x)=f(|g(x)|) and h_(2)(x)=|f(g(x))|. Which of the following is not true about h_(1)(x) ?