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inte^(ax)sinbxdx is:...

`inte^(ax)sinbxdx` is:

A

`(e^(ax))/(a^(2)+b^(2))(acosbx+bsinbx)+c`

B

`(e^(ax))/(a^(2)+b^(2))(asinbx+bcosbx)+c`

C

`(e^(ax))/(a^(2)+b^(2))(acosbx-bsinbx)+c`

D

`(e^(ax))/(a^(2)+b^(2))(asinbx-bcosbx)+c`

Text Solution

Verified by Experts

The correct Answer is:
D
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