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The inverse of A=[[cos theta, sin theta]...

The inverse of `A=[[cos theta, sin theta],[-sin theta,cos theta]]` is :

A

A

B

`-A`

C

`A^(T)`

D

`-A^(T)`

Text Solution

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The correct Answer is:
C
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Knowledge Check

  • If A=[[cos theta,sin theta],[-sin theta,cos theta]] and A(adj A)=[[k,0],[0,k]] , then k =

    A
    0
    B
    `sin theta`
    C
    `cos theta`
    D
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  • If A=[{:(cos theta, sin theta),(-sin theta, cos theta):}] then "A A"^(T) is :

    A
    A
    B
    `A^(T)`
    C
    I
    D
    0

  • If A= [(cos theta, sin theta),(-sin theta, cos theta)] and A (adj A) = [(k,0),(0,k)] then k =

    A
    0
    B
    sin `theta`
    C
    cos `theta`
    D
    1

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