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Given (x(1) + iy(1)) (x(2) + iy(2))…(x(n...

Given `(x_(1) + iy_(1)) (x_(2) + iy_(2))…(x_(n) + iy_(n))` = a + ib, show that
`sum_(r=1)^(n) tan^(-1)""(y_(r))/(x_(r))= tan^(-1)((b)/(a))+2k pi, " k " in ZZ`

Text Solution

Verified by Experts

The correct Answer is:
`sum_(r21)^(n)tan^(-1)((y_(r ))/(x_(r )))=tan^(-1)((b)/(a))+2kpi k in Z`
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