For any four vectors `veca, vecb, vec c , vecd` (all non coplanar) any vector can be written as a linear combination of other three vectors.

If non-zero vectors veca and vecb are equally inclined to coplanar vector vecc , then vecc can be

For any non-zero vectors vec(a)andvec(b)vec(a)xxvec(b) is

If veca , vecb , vecc and vecd are four non-coplanar unit vectors such that vecd makes equal angles with all the three vectors veca, vecb, vecc then prove that [vecd vecavecb]=[vecd veccvecb]=[vecd veccveca]

For any three vectors veca, vec b, vec c prove that (vec a + vec b)+ vec c = vec a + (vec b + vec c)

For any two vectors veca and vecb|veca X vecb|^(2)+|veca.vecb| is:

For any non-zero vectors vec(a),vec(b)andvec(c),(vec(a)xxvec(b)).vec(c) is

For any two vectors veca and vec b show that |vec a. vec b| le |vec a||vec b| .

Given three vectors veca, vecb and vecc are non-zero and non-coplanar vectors. Then which of the following are coplanar.

Statement 1: veca, vecb and vecc are three mutually perpendicular unit vectors and vecd is a vector such that veca, vecb, vecc and vecd are non- coplanar. If [vecd vecb vecc] = [vecdvecavecb] = [vecdvecc veca] = 1, " then " vecd= veca+vecb+vecc Statement 2: [vecd vecb vecc] = [vecd veca vecb] = [vecdveccveca] Rightarrow vecd is equally inclined to veca, vecb and vecc . Option A: Both the statements are true and statement 2 is the correct explanation for statement 1. Option B: Both statements are true but statement 2 is not the correct explanation for statement 1. Option C: Statement 1 is true and Statement 2 is false Option D: Statement 1 is false and Statement 2 is true.

If vectors veca and vecb are non collinear then veca/(|veca|)+vecb/(|vecb|) is