If the line (x-2)/(3)=(y-1)/(-5)=(z+2)/(...

If the line `(x-2)/(3)=(y-1)/(-5)=(z+2)/(2)" lies in the plane "x+3y-az+beta=0" then "(alpha,beta)` is

(-5, 5)

(-6, 7)

(5, -5)

(6, -7)

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PREMIERS PUBLISHERS-APPLICATIONS OF VECTOR ALGEBRA-SOLUTION TO EXERCISE 6.10

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