A particle moves along a line according to the law `s(t)=2t^(3)-9t^(2)+12t-4`, where `tge0`.
Find the total distance travelled by the particle in the first 4 seconds.

A particle moves along a line according to the law s(t)=2t^(3)-9t^(2)+12t-4 , where tge0 . Find the particle's acceleration each time the velocity is zero.

A particle moves along a line according to the law s(t)=2t^(3)-9t^(2)+12t-4 , where tge0 . At what times the particle changes direction?

A particle moves along a horizontal line such that its equation of motion is s(t) = 2t^(3) - 15t^(2) + 24t -2 , s in meters and t in second. Find the total distance travelled by the particle in the first 2 seconds.

Find the distance travelled by the particle during the time t = 0 to t = 3 second from the figure .

The equation for the motion of a particle is v = at . The distance travelled by the particle in the first 4 second is :

A particle moves so that the distance moved is according to the law s(t)=(t^(3))/(3)-t^(2)+3 . At what time the velocity and acceleration are zero respectively ?

Figure shows the speed versus time graph for a particle. Find the distance travelled by the particle during the time t=0 to t=3s.