A particle moves along a line according to the law `s(t)=2t^(3)-9t^(2)+12t-4`, where `tge0`.
Find the particle's acceleration each time the velocity is zero.

A particle moves along a line according to the law s(t)=2t^(3)-9t^(2)+12t-4 , where tge0 . At what times the particle changes direction?

A particle moves along a line according to the law s(t)=2t^(3)-9t^(2)+12t-4 , where tge0 . Find the total distance travelled by the particle in the first 4 seconds.

A particle moves so that the distance moved is according to the law s(t)=(t^(3))/(3)-t^(2)+3 . At what time the velocity and acceleration are zero respectively ?

A particle moves so that the distance moved is according to the law s(t)=t^3/3-t^2+3 . At what time the velocity and acceleration are zero respectively?

If a particle moves is a straight line according to s=t^(3)-6t^(2)-15t , the time interval during which the velocity is negative and acceleration is positive is

A particle moves along the X-axis as x=u(t-2 s)+a(t-2 s)^2 .

A particle moves in a straight line according to the relation: x = t ^ { 3 } - 4 t ^ { 2 } + 3 t Find the acceleration of the particle at displacement equal to zero.

A ball is thrown vertically upwards, moves according to the law s=13.8t-4.9t^(2) where s is in metres and t is in seconds. (i) Find the acceleration at t = 1 (ii) Find velocity at t = 1 (iii) Find the maximum height reached by the ball?