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(x^(2)+y^(2))dy=xydx. It is given that y...

`(x^(2)+y^(2))dy=xydx`. It is given that `y(1)=1` and `y(x_(0))=e`. Find the vale of `x_(0)`.

Text Solution

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The correct Answer is:
`x_(0) = pm sqrt(3e)`
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