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Show that (i) ~(p wedge q) -= ~p vee ~q ...

Show that (i) `~(p wedge q) -= ~p vee ~q`
(ii) `~(p to q) -= p wedge~q`.

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PREMIERS PUBLISHERS-DISCRETE MATHEMATICS-Problems For Practice
  1. Show that (i) ~(p wedge q) -= ~p vee ~q (ii) ~(p to q) -= p wedge~q.

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  2. Which of the following is a contradiction?

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  3. + is not a binary operation on

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  4. The value of (""(11)[3]""+""(11)[5])+""(11)[6] is:

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  5. divide is a binary operation on:

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  6. Which condictional statement p to q is equivalent to :

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  7. The number of rows of the truth table of -(p wedge (-q)) wedge q is:

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  8. If * defined as a * b =a^(2)+b^(2)-ab then 3 * (4 * 2) is

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  9. If p is true and q is false, then which of the following is not true?

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  10. p leftrightarrow q is equivalent to:

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  11. In the set of integers under the operation * defined by a * b =a+b-5 t...

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  12. Let p be 'Anand is going to school' q be there are twenty five student...

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  13. Which of the following is a tautology?

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  14. In a set of real numbers an operations * defined by a * b=sqrt(a^(2) +...

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  15. Which of the following is not a binary operation on R?

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  16. Which of the following is/are not statement? (i) Three plus four is ...

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  17. In a compound statement which is made of 4 single statement then the n...

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  18. Which of the following are statement? (i) 7 +2 lt 10 (ii) Set of rat...

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  19. In congruence modulo 5, {x in Z//x=5k +2} represents.

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  20. In (S, **), is defined by x ** y =x where x, y in S, then

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  21. Which one of the following is not a statement?

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