Home
Class 12
MATHS
The volume of the solid that results whe...

The volume of the solid that results when the region enclosed by `(x^(2))/(a^(2)) +(y^(2))/(b^(2)) = 1` is revolved about the minor axis is :

A

`1/2 pi ab^(2)`

B

`4/3 pi a^(2)b`

C

`4/3 pi ab^(2)`

D

`3/4 pi a^(2)b`

Text Solution

Verified by Experts

Promotional Banner

Topper's Solved these Questions

  • MODEL QUESTION PAPER - II

    PREMIERS PUBLISHERS|Exercise PART-II|10 Videos
  • MODEL QUESTION PAPER - II

    PREMIERS PUBLISHERS|Exercise PART-III|10 Videos
  • INVERSE TRIGONOMETRIC FUNCTIONS

    PREMIERS PUBLISHERS|Exercise PROBLEMS FOR PRACTICE ( ANSWER THE FOLLOWING QUESTIONS ):|24 Videos
  • MODEL QUESTION PAPER -1

    PREMIERS PUBLISHERS|Exercise Part -IV|20 Videos

Similar Questions

Explore conceptually related problems

The area enclosed by the ellipse (x^(2))/(a^(2)) + (y^(2))/(b^(2)) = 1 is equal to

Find the volume of solid that results when the region enclosed by the curve y=1+x^2,x=0,x=2,y=0 is revolved about the x axis.

Find the volume of the solid generated when the region enclosed by y=sqrt(x),y=3 and x=0 is revolved about y axis.

Volume of solid obtained by revolving the area of the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 about major and minor axes are in tha ratio……

Find the volume of the solid of revolution when the region bounded by y=sqrt(x), y=2 and x=0 is rotated about the x axis .

The volume of solid of revolution of the region bounded by y^(2)= x( a-x) about x-axis is

Find the volume of ellipsoid when the ellipse (x^2)/(a^2)+(y^2)/(b^2)=1 revolves around x axis .