The centre of a circle passing through (0,0), (1,0) and touching the CircIe `x^2+y^2=9` is a. `(1/2,sqrt2)` b. `(1/2,3/sqrt2)` c. `(3/2,1/sqrt2)` d. `(1/2,-1/sqrt2)`

The centre of a circle passing through (0,0),(1,0) and touching the Circle x^(2)+y^(2)=9 is a a ((1)/(2),sqrt(2)) b.((1)/(2),(3)/(sqrt(2))) c.((3)/(2),(1)/(sqrt(2))) d.((1)/(2),-(1)/(sqrt(2)))

Show that the centre of the circle passing through the points (0,0) and (1,0) and touching the circle x^(2)+y^(2)=9 is (1/2,+-sqrt(2))

The centre of the circle passing through (0.0) and (1,0) and touching the circle x^(2)+y^(2)=a^(2)is:(A)(1/2,1/2)(B)((1)/(2),-sqrt(2))(C)(3/2,1/2)(D)(1/2,3/2)'

The center(s) of the circle(s) passing through the points (0,0) and (1,0) and touching the circle x^(2)+y^(2)=9 is (are) ( a) ((3)/(2),(1)/(2)) (b) ((1)/(2),(3)/(2))(c)((1)/(2),2(1)/(2)) (d) ((1)/(2),-2(1)/(2))

A circle passes through (0,0) and (1,0) and touches the circle x^(2)+y^(2)=9 then the centre of circle is -

The equation to the tangent to the circle x^2+y^2+2x-1=0 at (-1,sqrt2) is

Let C be the circle with centre at (1, 1) and radius = 1. If T is the circle centred at (0, y), passing through origin and touching the circle C externally, then the radius of T is equal to (1) (sqrt(3))/(sqrt(2)) (2) (sqrt(3))/2 (3) 1/2 (3) 1/4

Let C be the circle with centre at (1, 1) and radius = 1. If T is the circle centred at (0, y), passing through origin and touching the circle C externally, then the radius of T is equal to (1) (sqrt(3))/(sqrt(2)) (2) (sqrt(3))/2 (3) 1/2 (3) 1/4

Let C be the circle with centre at (1, 1) and radius = 1. If T is the circle centred at (0, y), passing through origin and touching the circle C externally, then the radius of T is equal to (1) (sqrt(3))/(sqrt(2)) (2) (sqrt(3))/2 (3) 1/2 (3) 1/4