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The measurement value of length of a sim...

The measurement value of length of a simple pendulum is 20 cm known with 2 mm accuracy. The time for 50 oscillations was measured to be 40 s within 1s resolution. Calculate the percentage accuracy in the determination of acceleration due to gravity g from the above measurement.

Text Solution

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Since, `T=2pi sqrt(L//g)`
`g=4pi^(2)(L//T^(2))`
So, `(Deltag)/(g)xx100=((DeltaL)/(L)xx100)+2((DeltaT)/(T))`
`=((0.2)/(20))xx100+2((1)/(40))xx100`
`=1+5=6%`
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