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The least count of stop watch is 0.5s. T...

The least count of stop watch is 0.5s. The time of 40 oscillation of the pendulum is found to be 40s. The percentage error in the measurement of time period is ……………… `%`

A

0.75

B

0.5

C

1.25

D

0.25

Text Solution

Verified by Experts

The correct Answer is:
C
`"Least count = 0.5a"`
`DeltaT=0.5a`
`T=40`
`%" Error "=(DeltaT)/(T)xx100`
`=(0.5)/(40)xx100=(50)/(40)=1.25`
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