In an experiment four quantities, a, b, c and d are measured with `%` error `1%, 2%, 3% and 4%` respectively. If the quantity A is calculated as `A=(a^(3)b^(2))/(cd)` the `%` error in A is :

Options

A. `4%`
B. `28%`
C. `14%`
D. `7%`

Answer

C

Explanation

`A=(a^(3)b^(2))/(cd)`
`(DeltaA)/(A)=3((Deltaa)/(a))+2((Deltab)/(b))+((Deltac)/(c ))+((Deltad)/(d))`
`=3(1%)+2(2%)+3(%)+4%`
`=14%`