An object is thrown with initial speed `5ms^(-1)` with an angle of projection `30^(@)`. What is the maximum height and range reached by the particle?

Explanation

Given : `theta = 30^(@) , u = 5 m//s`
Formula : `h = (u^(2) sin^(2) theta)/(2g)`
`R = (u^(2) sin^(2) theta)/(g)`
(i) ` h = (u^(2) sin ^(2) theta)/(2g)`
` = ((5)^(2) sin^(2)(30^(@)))/(2 xx 9 . 8) = (25)/(78 . 4)`
h = 0 . 318 m
(ii) `R = (u^(2) sin 2 theta)/(g)`
`= ((5)^(2) sin 2 xx 30^(@))/(9.8) `
` = (25^(@))/(9 . 8) xx (sqrt(3))/(2)`
` R = (43.30)/(19.6) = 2.21 m `