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The angle of projection for a projectile...

The angle of projection for a projectile to cover maximum range is :

A

`30^(@)`

B

`60^(@)`

C

`0^(@)`

D

`45^(@)`

Text Solution

Verified by Experts

The correct Answer is:
D
`R_(max")= (u^(2))/(g)`
`(u^(2))/(g) sin 2 theta = (u^(2))/(g) ` .
`sin 2 theta = 1`
`:. 2 theta = 90^(@)`
`theta = 45^(@)`
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