Calculate the maximum horizontal range attained by the particle in the case of oblique projection.

Explanation

We know that horizontal range ,
`R = (u^(2) sin 2 theta)/( g)`
for R to be maximum u and g are constant.
Therefore variable is ` ' theta'` .
i.e., ` sin 2 theta = 90^(@)`
` :. theta = 45^(@)`