A body is projected upwards with a velocity of `30ms^(-1)` at an angle of `30^(@)` with the horizontal . Determine .
the time of flight

Explanation

Given :
Velocity v =30 m//s
Angle of projection , `theta = 30^(@)`
Time of flight
` t_(f) = (2 u sin theta)/( g) = (2 xx 30 xx sin 30^(@))/( 9 . 8)`
`= ( 2 xx 30)/( 9 . 8) xx (1)/(2)`
`t_(f) = 3 . 0 6` s