A body is projected upwards with a velocity of `30ms^(-1)` at an angle of `30^(@)` with the horizontal . Determine .
the maximu height attained by the dody .

Explanation

Given :
Velocity v =30 m//s
Angle of projection , `theta = 30^(@)`
Maximum height attained by the body,
`h_("max") = (u^(2) sin^(2) theta)/( 2g)`
`= (30 xx 30 xx sin ^(2) 30^(@))/( 2 xx 9 .8)`
`= (30 xx 30)/( 2 xx 9 . 8) xx (1)/(2) xx (1)/(2)`
= 11 . 479 m = 11 . 48m