Explain the variation of 'g' with latitude.

Explanation

An object is on the surface of the Earth, experiences a centrifugal force that depends on the latitude of the object on Earth. If the Earth were not spinning, the force on the object would have been mg. An additional centrifugal force due to spinning of the Earth, is experienced by the object.
`to` refer figure no. 6.2.
This centrifugal force is given by `momega^(2)R'`.
`R'=Rcoslambda`
where `lambda` is the latitude. The component of centrifugal acceleration experienced by the object in the direction opposite to acceleration due to gravity is
`a_(PQ)=omega^(2)R'coslambda=omega^(2)Rcos^(2)lambda`
since `R'=Rcoslambda`
`thereforeg'=g-omega^(2)Rcos^(2)lambda`