A barometer kept an elevator accelerating upwards reads 76cm of Hg. If the elevator is accelerated upwards at `4.9ms^(-2)`, then calculate the air pressure in the elevator?

Explanation

Height `h=76cm`
Acceleration `a=4.9ms^(-2)`
When the elevator moves upward with acceleration a,
`{:("Net"),("acceleration"):}}=g+a`
`=9.8+4.9`
`=14.7m//s^(2)`
`{:("Air pressure"),("in the elevator"):}}P=hrho(g+a)`
`P=76xx13.6xx14.7`
`P=151.9cm` of Hg.