The length of a rod as measured in an experiment was found to be 3.48, 3.46, 3.49m, 3.50m and 3.48m. Find the average length, the absolute error in each observation and percentage error.

Explanation

Average length
`=(3.48+3.46+3.49+3.50+3.48)/(5)`
`=(17.41)/(5)`
`=3.482m=3.48m`
(Round off to 2 places of decimal point)
The absolute erros in the different measurements are
`DeltaL_(1)=3.48-3.48=0.00m`
`DeltaL_(2)=3.48-3.46=002 m`
`DeltaL_(3)=3.48-3.49=-0.01 m`
`DeltaL_(4)=3.48-3.50=-0.02m`
`DeltaL_(5)=3.48-3.48=0.00m`
The absolute error `=(Sigma|DeltaL_(i)|)/(5)`
`=(0.00+0.02+0.01+0.02+0.00)/(5)`
`=(0.05)/(5)=0.01m`
`therefore " Correct length"=3.48 pm 0.01m`
`"Percentage error "=(0.01)/(3.48)xx100=0.29%`