The percentage errors in the measurement of length and time period of a simple pendulum are `1% and 2%` respectively. Then find the maximum error in the measurement of acceleration due to gravity.

Explanation

Time period of a simple pendulum is
`T=2pisqrt((L)/(g)) rArr g=(4pi^(2)L)/(T^(2))`
`therefore (Deltag)/(g)xx100=((DeltaL)/(L)+2(DeltaT)/(T))xx100`
`=1%+2xx2%=5%`