If the length and time period of an oscillating pendulum have errors of `2% and 5%` respectively, what is the error in the estimate of g?

Explanation

Acceleration due to gravity
`g=(4pi^(2)l)/(T^(2))`
`therefore (Deltag)/(g)xx100=(Deltal)/(l)xx100+2(DeltaT)/(T)`
`=2%+2xx5%=12%`