The period of oscillation of a simple pendulum is given by `T=2pi sqrt((l)/(g))`. In finding the value of g, which quantity should be measured most accurately and why?

Explanation

`T=2pi sqrt((l)/(g)) rArr T^(2)=(4pi^(2)l)/(g)`
`or g=4pi^(2)(l)/(T^(2))`
`therefore" Fractional error in g"=(Deltag)/(g)=(Deltal)/(l)+(2DeltaT)/(T)`
Note that any error in T is doubled up. Therefore, time should be measured most accurately.