Two objects of masses `m_(1) and m_(2)` fall from the heights `h_(1) and h_(2)` respectively. The ratio of the magntidue of their momenta when they hit the ground is

Options

A. `sqrt((h_(1))/(h_(2)))`
B. `sqrt((m_(1)h_(1))/(m_(2)h_(2)))`
C. `(m_(1))/(m_(2))sqrt((h_(1))/(h_(2)))`
D. `(m_(1))/(m_(2))`

Answer

C

Explanation

`v^(2) = u^(2) = 2as`
u= 0, a = g, s = h
`v = sqrt(2 gh)`
`P = mv, " " P_(1) = m_(1)v_(1) = m_(1) sqrt(2gh_(1))`
`P_(2) = m_(2) v_(2) = m_(2) sqrt(2gh_(2))`
`(P_(1))/(P_(2)) = (m_(1))/(m_(2)) sqrt((h_(1))/(h_(2)))`