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A water fountain on the ground sprinkles...

A water fountain on the ground sprinkles water all around it. If the speed of the water coming out of the fountain is v. Calculate the total area around the fountain that gets wet.

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Formula: `A = pi R^(2) " ". . . (1)`
Here, `R = R_("max") = ((v^(2))/(g)) sin 2 (45^(@)) `
`R_("max") = (v^(2))/(g) " ". . . (2)`
Substituting (2) in (1) `A = (pi v^(4))/(g^(2))`
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