If an object is thrown horizontally with an initial speed `"10 ms"^(-1)` from the top of a building of height 100 m. What is the horizontal distance covered by the particle.

Explanation

Given: u = 10 m/s
h = 100 m
Horizontal distance
` :. R = u sqrt((2h)/(g)) rArr 10 sqrt((2 xx 100)/(9 . 8 ))`
`= 10 sqrt((200)/(9 . 8)) = 10 sqrt(20 . 40)`
= 10 (4 . 516)
R = 45 . 16 m