An object is executing uniform circular motion with an angular speed of `(pi)/(12)` radian per second. At `t=0`, the object starts at an angle` theta=0`. What is the angular displacement of the particle after 4s?

Explanation

Given : `omega = (pi)/(12)`
`t = 0, theta = 0^(@) , omega _(0) = 0`
At t = 4s , ` theta = ? ? `
Formula:
Angular displacement
`theta = ((omega_(0)+ omega)/(2))t`
` =((0 + pi)/(12 xx 2)) 4`
` = (pi)/(24) xx 4 rArr (pi)/(6) = (180^(@))/(6)`
`30^(@)`