The displacement of a body is given by ` x = 2t^(3) - 6t^(2) + 12t + 6` . The acceleration of body is zero at time ti is equal to :

Options

A. 3s
B. 2s
C. 1s
D. 10s

Answer

C

Explanation

`x = 2t^(2) - 6t^(2) + 12t +6`
`v = (dx)/(dt) = (d)/(dt) (2t^(3) - 6t^(2) +12t +6)`
`= 2 xx 3t^(2) - 6 xx 2t +12`
`= 6t^(2) - 12t + 12`
`a = (dv)/(dt) = (d)/(dt) (6t^(2) - 12t+12)`
`= 6 xx 2t - 12`
`= 12t - 12`
Since a = 0
12t - 12 = 0
12t = 12
`:. t = (12)/(12) = 1s`
t = 1s