A tiger chases a deer 30 m ahead of it and gains 3 m in 5 second after the chase began . The distance gained by the tiger in 10 second is :

Options

A. 18m
B. 20m
C. 6m
D. 12m

Answer

D

Explanation

If a the relative acceleration then `s = (1)/(2) at^(2)`
When t = 5s, s = 3
`3 = (1)/(2) xx axx (5)^(2)`
6 = 25 a
`:. a = (6)/(25) m//s^(2)`
when ` t = 10s, a = (6)/(25) m//s^(2) , s = ?`
`s = (1)/(2) xx (6)/(25) xx (10)^(2)`
`= (1)/(2) xx (6)/(25) xx 100 = 12m`
`:.` The distance gained = 12 m