During a projectile motion if the maximum height equals the horizontal range,then the angle of projection with the horizontal is :

Options

A. `tan^(-1) (1)`
B. `tan^(-1) (2)`
C. `tan^(-1) (3)`
D. `tan^(-1) (4)`

Answer

D

Explanation

`(u^(2) sin ^(2) theta)/(2g) = (u^(2) sin 2 theta)/(g)`
`:. (sin^(2)theta)/(2) = 2 sin theta cos theta`
`:. (sin theta)/( cos theta) = 4`
`tan theta = 4`
`:. theta = tan^(-1)(4)`