The velocity of a particle is given by the equation, `v = 2t^(2) + 5 cms^(-1) ` . Find
the instantaneous acceleration at `t_(2) = 4s`

Explanation

Given ` v = (2 t^(2) +5) cms^(-1)`
Instantaneous acceleration
`a = (dv)/(dt) = (d)/(dt) =(2t^(2) +5) = 4t`
At t = 4s, a = `4 xx 4 = 16 cms^(-2)`