When the angle of elevation of a gun are `60^(@) and 30^(@)` respectively . The heights it shoots are `h_(2) and h_(2)` respectively . Find the ration `h_(2) //h_(2)` .

Explanation

For angle of elevation of `60^(@)` we have maximum height
`h_(1) = (u^(2) sin^(2) 60^(@))/(2g) = (3u^(2))/(8g)`
For angle of elevation of `30^(@)` , we have maximum height
`h_(2) = (u^(2) sin ^(2) 30^( @))/(2g) = (u^(2))/(8g)`
`:. (h_(1))/(h_(2)) = (3)/(1)`