Three blocks masses 4kg 6kg and 8kg are connected by a string they are placed on a frictionless surface if the system is pulled by a force of F=36 N then acceleration of the body is a = and tension acting on the sting is T= Which of the following pair is correct

Options

A. `a=4 m//s^(2),T=14 N`
B. `a=8 m//s^(2),T=7 N`
C. `a=16 m//s^(2),T=196 N`
D. `a=4 m//s^(2),T=28 N`

Answer

d

Explanation

Acceleration a =` (F )/( m_(1)+ m_(2) + m_(3))`
`= (36)/( 4+ 6+8) = (36)/(18) = 2m//s^(2)`
By Newton second law

`4a = 36 - T_(1)`
`=36 - 4 xx 2`
`=36-8`
`28N`