A machine gun fires a bullet of mass 40 g with a speed of 1200 `ms^(-1)` the person holding the gun can exert a maximum force 144 N on it what is the number of bullets that can be fired from the gun per second

Explanation

given m=45 g
v= 120`ms^(-1)`
Force 144 N
Let maximum number of bullets that can be fired per second = n
Change in momentum of n bullets
= nm (v-u)
`= nxx (40)/(1000) (1200 -0)`
As impulse = change in momentum
Ft= 48 N
Number of bullets
`N= (Ft )/( 48) = (144 xx 1)/(48) =3` bullets / s