The initial speed of a body of mass 2.0 kg is `5.0 ms^(-1)` a force fro 4s in the direction of motion of the body the force time graph is shown in the diagram calculate the impulse of the force and the final speed of the body

Explanation

Given mass = 2.0 kg
Initial speed =5.0 `ms^(-1)`

Formula
Impulse of a force

`=(1)/(2) xx 1.5 xx 3 + 1 xx 3 + (1)/(2)`
`=(1)/(2) xx 4.5 + 3 + (1)/(2) xx 5 xx 0.5 +2`
`=2.25 + 3+ 1.25 + 2= 8.50 Ns`
As Impulse = change in momentum
`=mDelta v`
Change in velocity
`Delta v = ("impulse")/( m ) = (8.50)/(2) `
Final speed of the body Initial speed `+Delta v = 5.0 + 4.25 = 9.25 ms^(-1)`